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Add RECEPTOR_KEEP_WORK_ON_ERROR setting

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If RECEPTOR_KEEP_WORK_ON_ERROR is set to true receptor work unit will not be automatically released

Co-Authored-By: Chris Meyers <chrismeyersfsu@users.noreply.github.com>
This commit is contained in:
Hao Liu
2024-07-22 12:32:53 -04:00
parent 7691365aea
commit 139d8f0ae2
5 changed files with 24 additions and 6 deletions
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9
awx/main/tasks/receptor.py
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@@ -405,10 +405,11 @@ class AWXReceptorJob:
finally:
# Make sure to always release the work unit if we established it
if self.unit_id is not None and settings.RECEPTOR_RELEASE_WORK:
try:
receptor_ctl.simple_command(f"work release {self.unit_id}")
except Exception:
logger.exception(f"Error releasing work unit {self.unit_id}.")
if settings.RECPETOR_KEEP_WORK_ON_ERROR and getattr(res, 'status', 'error') == 'error':
try:
receptor_ctl.simple_command(f"work release {self.unit_id}")
except Exception:
logger.exception(f"Error releasing work unit {self.unit_id}.")
def _run_internal(self, receptor_ctl):
# Create a socketpair. Where the left side will be used for writing our payload